May 19, 2006, 12:24 am

Hello Folks. This is my small contribution to all the great people on this site.This is for the Pick 3 system. Pick 4 will be done later. The workup takes 15 minutes. With a small program, it'll take seconds.

My method is called DSUM as in 'dee-some'. No kidding-It works 100% of the time. Let me repeat, ****100%****. I have used it and I whave won on Betslips everytime I have played. Its been $37.50, $75.00, $300.00, etc...everytime I have played. The only time I don't win or don't win consistently is when I try other systems and start experimenting.

I win every draw that is held. The small problem is filtering just a little bit more. Just a little. Maybe you guys can help refine. Its not complicated. Here it goes:

The DSUM method starts out with the base 10, which is the source from which all numbers spring. The base is the wrap method.ou know, you take the last draw and add 1 to each number until the number wraps around to itself. For example take the number 472--

"D" is for down. You only **ever** need go down by **1 digit only**. Example is 7 goes to 6, or 9 goes to 8.

"S" is for Same. The number stays the same.

"U" is for Up. You only **ever** need go up by **1 digit only**. Example is 7 goes to 8 or 9 goes to 0.

"M" is for Mirror. You put in the mirror of a number. Example is 9 goes to 4 or 6 goes to 1.

You only have to go up and down by 1 digit only.

Now each 3 digit number in a draw has only 64 possible permutations. 16 for "D", 16 for "S", 16 for "U" and 16 for "S". Using the draw **472. **You just have to **permutate 472 through D-S-U-M** and then wrap down that permutation. Take a look and notice how you will get many duplicates. All but one can be eliminated. Again, its not complicated. Stay with it. Here's the formula

** DSUM**

** of 4 7 2**

**The D's**

** 1 2 3 4 5 6 7 8 **

**DDD** ** DDS DDU DDM DSD DSS DSU DSM **

361 362 363 367 371 **372** 373 377

472 473 474 478 482 483 484 488

583 584 585 589 593 594 595 599

694 etc... etc... etc... 604 605 etc... etc...

705 **Wrap each of these 8 columns** **down.**

816

927 ETC

038

149

250 251 252 256 260 261 262 266

** **

** 9 10 11 12 13 14 15 16**

**DUD DUS DUU DUM DMD DMS DMU DMM**

381 382 383 387 321 322 323 327

** ****Wrap each of these 8 columns down. **

**Now we do the S's for "472"**

** 17 18 19 20 21 22 23 24**

**SDD SDS SDU SDM SSD SSS SSU SSM**

461 462 463 467 471 472 473 477

572 573 574 578 582 583 584 588

**Wrap each of these 8 columns** **down.**

**25 26 27 28 29 30 31 32**

**SUD SUS SUU SUM SMD SMS SMU SMM**

481 482 483 487 421 422 423 427

**Wrap each of these 8 columns** **down.**

**Now the U's for 472**

** 33 34 35 36 37 38 39 40**

**UDD UDS** **UDU UDM USD USS USU USM**

**561 562 563 567 571 572 573 577**

**Wrap each of these 8 columns** **down. **

**41 42 43 44 45 46 47 48 **

**UUD UUS UUU UUM UMD UMS UMU UMM**

581 582 583 587 521 522 523 527

**Wrap each of these 16 columns** **down.**

** Now the M's for 472**

**49 50 51 52 53 54 55 56**

**MDD MDS MDU MDM MSD MSS MSU MSM**

961 962 963 967 971 972 973 977

**Wrap each of these 16 columns** **down.**

** 57** **58 59 60 61 62 63 64**

**MUD MUS MUU MUM MMD MMS MMU MMM**

981 982 983 987 927 922 923 927

**Wrap each of these 16 columns** **down.**

The number of the next draw will absolutely be found in the above wraps.

There will be about 38 - 40 columns that will be duplicates and those can

eliminated. You will have 20 columns of the 64 that will used to find the next

draw. You can look at the numbers by columns or by rows. Rows are

interesting , because **one** number in the **original **base 10 can **always** be

permutated by one of the DSUM manipulatins to find the winning answer.

Again I have laid out all the possible permuations. Since you don't know how

to exactly tweak or permutate the number you play the whole string across.

You will end up with 20 numbers. The problem I'm having is finding a good

strong pointer in one row of the **original** base 10 column. Remember, the

original base 10 is to take the last draw and do the wrap. Perform DSUM on

that number, and play the string of numbers in that row. If you're not sure

whcih number to pick, like I often am you will have to pick ad just not from

only 1 row, but all ten rows of 20 colums.

At this point I look at the last five draws to help me elimante the numbers

that will not probably come out. If playing by betslips it becomes very

profitable. I'll eventually try to end up with 50.

Anyone can apply any other method to help pull out the winning

number. You can use any other valid method on this site to filter out the

unlikely numbers, and come up with the winning draw. Remember the

winning number is there 100% of the time. The only problem is finding the

valid pointer. Another strong technique I combine with the above method is

to help find the next draw is to take the previous draw, and find the six

combos. For example, take 472 again. The combos are:

472

427

274

247

742

724

In the case of doubles you would have 3 combos. Now you take the

combos and divide each by pi - you know 3.14. Put the result in 4 columns.

In the 1st column is just the result from dividing by pi. In the 2nd column

you add 111 to the original result. In the 3rd column you add 666 to the

original result, and in the 4th and last column you add 888 to the original result.

I have found that you don't really need the 888 column. I just like to. Often

times you will see the numbers converging in a pattern, they will

converge on a certain number. Even if they don't I will merge this second

technique with DSUM. I always come out with the right number.

If you back-test DSUM you will find the winner is there

everytime. The system is very profitable online with betslips. I made about

$600 bucks in several days, by winniing incrementally in every draw. I just

don'y like playing many numbers. Can any brilliant mind find a somewhat

perfect way to filter? or simply or I guess rather not simply, find the way to

the row in the original base 10. If you can, oh boy--you will win everytime,

beacsue the permutaition willbe in that row. If you were to play all 64

'tweaks' you would hit **STRAIGHT WITHOUT FAIL!!!**

My pick 4 method is like the one above. Its just that there are a lot more

columns. It works just as well. I have done the Pick 5 work through as well.

Only thing is that I have to make sure that there is the same resonance with

the numbers that exist in Pick 3 and Pick 4. I'm trying to see how my DSUM

would work on the numbers. For example to go down a digit in Pick 5 would

I do 23 to 22 or 23 to 12. The same goes for the mirrors of these numbers.

I've beenavoiding it beacuse it will be a herculean effort. I needto leran

some programming.it wille done though, because the implications, at least

for me, is mouth-watering. This DSUM method works for me.

Oh by the way,

another much simpler way to always get the final draw it to forget the DSUM

Wraps, and just take the 6 combos of the last draw divided by Pi with 111,

666, and/or 888 added to them and perform a **DSUM string for eah **

**number without the ****Wraps** on them. Then filter out the duplicates and the

unlikely numbers. The winning draw will **always** be found there. I hope I

was somewhat coherent in my explanation. and I hope some people find

this very useful. I'm working on finding the strong pointer. Oncei get it. It

will be shown. Wouldn't it be great to play just 20 numbers, and know that

wiithout a doubt your winning number will always be found there. Until

later....Ciao.

Kola

May 19, 2006, 12:39 am

Kola again...

To do a little test. Take the **second to last draw** and do a wrap of that number. You will find the **last draw** winning number in that **second to last draw's wrap.** Always. Its always found in the permution of one number in that wrap, using DSUM. Down 1, Up 1, Same, and Mirror. Ciao

**Kola**

May 19, 2006, 1:32 am

Pacattack helped to realize that my epxlanation odf DSUM may have been too convulted. Here's a brief summary attempt.

Hey Pacattack. Much respect. I wish I could. I'll try.

1. take the last draw.

2. do a wrap of that number.

3. Use DSUM. Down 1 digit, Stay the same, Up one digit, and miror the digit.

There are only 64 possible combinations and DSUM covers them all. You will find

many duplicates

4. Formula is:

1. DDD 2. DDS 3. DDU 4. DDM 5. DSD 6. DSS 7. DSU 8. DSM

9. DUD 10. DUS 11. DUU 12. DUM 13. DMD 14. DMS 15. DMU 16. DMM

6. You have done the D's above. Now do the S's, the U's and the M's. Just change t

the first letter in each of the 16 sets above to S then U then M

7. You would have done all the possible ways the next number could come out.

Example of DDD on the number 472 is 361. and so on....

8. After you permutate or put the last draw in the formula above, then wrap each of

64 variations of the last draw. the winning number will be found in in one the

string or rows going across. **Always**. You will havemany duplicates, and you can

cross out those.The base 10 original is the source from where all future numbers

will spring.

9.The trick is finding the pointer in one of the original base ten numbers. If you can

do that you play the string across the winning number will always be found there.

10. secondly another technique using the above DSUM is to take the last draw,and

find its six combos. Example 672 is 672, 627, 276, 267, 726 , 762. divide each by

and then add 111 , 666, an/or 888 to the original result. Use DSUM on the

numbers you get and find the pattern. Sometimes the number converges on a

particular set of numbers. The winning numbers is always found after

DSUMMING the result from these combos.

I hope my explanation it was brief and succint. trhganks for forcimg me to simply.

I think I tried too hard to be thorough, and detailed in my first post. I'll be

posting some other interesting findings. Ciao.

May 19, 2006, 2:15 am

Kola I like the detailed explanation that you gave in the beginning. Everything cannot be put into a capsule form. It can become too compact & one is then unable to see all of the attributes.

May 19, 2006, 2:42 am

Kola I like the detailed explanation that you gave in the beginning. Everything cannot be put into a capsule form. It can become too compact & one is then unable to see all of the attributes.

Hmm...Well said. Thanks. I think that the problem may have been the spacing. It can look too dense, a little overwhelming and tricks the mind into believing its "too involved" if not spaced well. I tried to space it better, but when I posted it, it condensed. I guess there was a lot of dead space. Stay tuned then for some more detailed discoveries for the Pick 3 and 4. I'm testing a little bit more. You'll be delighted. As a matter of fact if it goes well...oh boy I'm excited. Accuracy, acccuracy accuracy. Until later Ciao.

May 19, 2006, 2:46 am

Pacattack helped to realize that my epxlanation odf DSUM may have been too convulted. Here's a brief summary attempt.

Hey Pacattack. Much respect. I wish I could. I'll try.

1. take the last draw.

2. do a wrap of that number.

3. Use DSUM. Down 1 digit, Stay the same, Up one digit, and miror the digit.

There are only 64 possible combinations and DSUM covers them all. You will find

many duplicates

4. Formula is:

1. DDD 2. DDS 3. DDU 4. DDM 5. DSD 6. DSS 7. DSU 8. DSM

9. DUD 10. DUS 11. DUU 12. DUM 13. DMD 14. DMS 15. DMU 16. DMM

6. You have done the D's above. Now do the S's, the U's and the M's. Just change t

the first letter in each of the 16 sets above to S then U then M

7. You would have done all the possible ways the next number could come out.

Example of DDD on the number 472 is 361. and so on....

8. After you permutate or put the last draw in the formula above, then wrap each of

64 variations of the last draw. the winning number will be found in in one the

string or rows going across. **Always**. You will havemany duplicates, and you can

cross out those.The base 10 original is the source from where all future numbers

will spring.

9.The trick is finding the pointer in one of the original base ten numbers. If you can

do that you play the string across the winning number will always be found there.

10. secondly another technique using the above DSUM is to take the last draw,and

find its six combos. Example 672 is 672, 627, 276, 267, 726 , 762. divide each by

and then add 111 , 666, an/or 888 to the original result. Use DSUM on the

numbers you get and find the pattern. Sometimes the number converges on a

particular set of numbers. The winning numbers is always found after

DSUMMING the result from these combos.

I hope my explanation it was brief and succint. trhganks for forcimg me to simply.

I think I tried too hard to be thorough, and detailed in my first post. I'll be

posting some other interesting findings. Ciao.

Oops in my summary above, I missed something. I t should read "Example 672 is

672, 627, 276, 267, 726 , 762. Divide each by **pi(3.14)**

and then add 111 , 666, an/or 888 to the original result.

May 19, 2006, 3:14 am

I am working on a spreadsheet for this. It takes a lot of time!! I am going to bed and will continue tomorrow, but I will share what I have done so far.

There are 64 columns and each is 10 numbers, so there will be a total of 640 numbers. I have completed through DUS which is only ten colums so far. I have a LONG way to go. So far no duplicates! Here are the numbers:

.

030 034 038 039 040 044 048 049 058 059 140 141 145 149 150 151 155 159 160 169 250 251 252 256 260 261 262 266 270 271 361 362 363 367 371 372 373 377 381 382 472 473 474 478 482 483 484 488 492 493 503 504 583 584 585 589 593 594 595 599 600 604 605 606 614 615 690 694 695 696 701 705 706 707 711 715 716 717 725 726 812 816 817 818 822 826 827 828 836 837 923 927 928 929 933 937 938 939 947 948

.

It looks like a very good method of finding ** where** to find the winning number will have to be developed.

I don't think I will be able to afford this system, but I will complete my spreadsheet tomorrow and share all of it.

May 19, 2006, 4:53 am

I am working on a spreadsheet for this. It takes a lot of time!! I am going to bed and will continue tomorrow, but I will share what I have done so far.

There are 64 columns and each is 10 numbers, so there will be a total of 640 numbers. I have completed through DUS which is only ten colums so far. I have a LONG way to go. So far no duplicates! Here are the numbers:

.

030 034 038 039 040 044 048 049 058 059 140 141 145 149 150 151 155 159 160 169 250 251 252 256 260 261 262 266 270 271 361 362 363 367 371 372 373 377 381 382 472 473 474 478 482 483 484 488 492 493 503 504 583 584 585 589 593 594 595 599 600 604 605 606 614 615 690 694 695 696 701 705 706 707 711 715 716 717 725 726 812 816 817 818 822 826 827 828 836 837 923 927 928 929 933 937 938 939 947 948

.

It looks like a very good method of finding ** where** to find the winning number will have to be developed.

I don't think I will be able to afford this system, but I will complete my spreadsheet tomorrow and share all of it.

Hi CalifDude,

The duplicates will alway turn up like 472 and then 274 or 724 etc.... You will

see them though and you will eliminate quite a number of columns. Sometimes

some of the duplicates are straights like 472 and 472.

The DSUM method can always be profitableif you pick the correct string or row

starting from the **original base 10 of DDD****and going across to MMM**. **JUST 1 OUT **

**TEN**. Instead of hundreds. Even if you picked two strings out of the base ten and

put a dollar on the 64 or really 62 possible combos (because SSS and DDD are the

same sets of numbers) you would have 124 combos. You would have bet 124

dollars. What would it matter? You would profit by 300-400 dollars - **Everytime.**

because in the string or row you would have the straight version of the number.

Again, I have greatly profited by using this system, and was inconsistent when I tried

experimenting with other systems. I hit the winning number **each time** even using

a filtering analysis that wasn't too strong. I would for example eliminate numbers

that came out in the last two weeks, look at the pattern of the last five draws and

use it to decide which numbers I would play. I need a stronger filtering system. A

pointer of sorts. Lottery Queen's method, lotterbraker's, Tntea's v-tracs,

blackapple's digit out root sum method, and others are easily applicable to

this system.

Check my first post on this thread and play with the pi method used with the last

draw combos, added with 111, 666, and 888. I have only been testing this pi

method a short time, but the winning combo numbers is **always** been found when

the results were permutated or DSUMMED. Often times you will see a convergence

of the disparate pi numbers into one or two numbers. Sometimes this is

accurate. But then again numbers are shizophrenic with different personalites-

different expressions. Using pi with DSUM is useful as well.

The pointer to the right string is "right there". I just got to pull back far enough.

I'll beposting some interesting observations with the Pick 3 and Pick 4. I

pluggedthem into a formula, and got some interesting paper results. Still tweaking

though. And it was so obvious too. Anyway coming soon. Thanks for giving the

method a workup CalifDude.

May 19, 2006, 5:00 am

**Thank you CD.**

**Will the combo be there straight or boxed only?**

Hey Lantern everytime you DSUM, you will have **all **the straight and boxed combos

in the string or row of 64. DSUM accounts for every possible permutation of the

next draw. If you can find the right string you can play all 64 permuations. You will

score the straight hit and a couple of boxed hits as well. Sometimes other strings

carry the same winning number as well.

Kola

May 19, 2006, 5:05 am

I am working on a spreadsheet for this. It takes a lot of time!! I am going to bed and will continue tomorrow, but I will share what I have done so far.

There are 64 columns and each is 10 numbers, so there will be a total of 640 numbers. I have completed through DUS which is only ten colums so far. I have a LONG way to go. So far no duplicates! Here are the numbers:

.

030 034 038 039 040 044 048 049 058 059 140 141 145 149 150 151 155 159 160 169 250 251 252 256 260 261 262 266 270 271 361 362 363 367 371 372 373 377 381 382 472 473 474 478 482 483 484 488 492 493 503 504 583 584 585 589 593 594 595 599 600 604 605 606 614 615 690 694 695 696 701 705 706 707 711 715 716 717 725 726 812 816 817 818 822 826 827 828 836 837 923 927 928 929 933 937 938 939 947 948

.

It looks like a very good method of finding ** where** to find the winning number will have to be developed.

I don't think I will be able to afford this system, but I will complete my spreadsheet tomorrow and share all of it.

One more thing CalifDude,

When looking for duplicates, then don't laways appear in the same row. The same

collective column of numbers will be there, but in a different position, and in a

different row, because of the digit up/down aspect of DSUM, and especially the

mirror

May 19, 2006, 5:56 am

It may be worthwhile to play a string of numbers and look five place up or down

the column and play its row of mirrors as well.

May 19, 2006, 6:45 am

Thanks Kola,

Since the winning number is there 100% of the time. This method can be used to eliminate numbers from other methods as well. Thanks again.

May 19, 2006, 6:46 am

Please go to https://www.lotterypost.com/thread/134729 for continuation of the topic.

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